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sm8 49

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PROBLEM (*8.49) Redo Prob. 8.48 for the case shown in Fig. P8.49.
*SOLUTION
18 MPa
y’
σ
x’
14 MPa
θ
x
σ x + σ y = σ x' + σ y'
30 − 20 = −18 + σ ;
σ x ' = 28 =
or
τ x' y'
σ = 28 MPa
30 − 20 30 + 20
+
cos 2θ + 10sin 2θ
2
2
23 = 25 cos 2θ + 10 sin 2θ
= −14 = −25 sin 2θ + 10 cos 2θ
Multiply this by − 2.5 :
35 = 62.5 sin 2θ − 25 cos 2θ
(1)
(2)
Add Eqs. (1) and (2),
58 = 72.5 sin 2θ , 2θ = 53.13o
or
θ = 26.6 o
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