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PROBLEM (8.18) Two triangular plates are weld together and subjected to biaxial stresses with σ x
= -5 MPa and
σy
= 15 MPa, as depicted in Fig. P8.18. Determine:
(a) The normal stress
(b) The shear stress
σw
τw
acting perpendicular to the weld.
acting parallel to the weld.
SOLUTION
We have
x’
θ = 25 + 90 = 115
σ x = −5 MPa
σ y = 15 MPa
τ xy = 0
σ x'
τ x' y'
θ
o
5 MPa
o
25
y’
x
15 MPa
1
1
(a) σ x ' = (σ x + σ y ) + (σ x − σ y ) cos 2θ
2
2
1
1
= (−5 + 15) + (−5 − 15) cos 230o = 11.43 MPa
2
2
Thus,
σ w = σ x ' = 11.43 MPa
1
(b) τ x ' y ' = − (σ x − σ y ) sin 2θ
2
1
= − (−5 − 15) sin 230o = −7.66 MPa
2
τw
So
τ w = τ x ' y ' = −7.66 MPa
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