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sm8 40

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PROBLEM (8.40) Given the stresses acting uniformly at the edges of a block (Fig. P8.40),
calculate:
(a) The stresses
σ x , σ y , and τ xy .
(b) The maximum shearing stresses with the associated normal stresses.
Sketch the results on properly oriented elements.
SOLUTION
σ y = −5sin 30o = −2.5 MPa
τ xy = 5cos 30o = 4.33 MPa
(a)
2.5 ΔA (0.866)
15 ΔA
30
ΔA
∑F
x
4.33 ΔA (0.866)
4.33 ΔA (0.5)
o
σ x ΔA (0.5)
= 0 : −15ΔA + 0.5ΔAσ x + 4.33ΔA(0.866) = 0 ,
22.5 + 2.5 2
) + 4.332 = 13.23 MPa
2
22.5 + 2.5
2θ s = tan −1[−
] = −70.9o
2(4.33)
σ ' = 12 ( 22.5 − 2.5) = 10 MPa
22.5 + 2.5
τ x' y' = −
sin(−70.9o ) + 4.33cos(−70.9)
2
= 11.81 + 1.42 = 13.23 MPa
Thus,
θ s ' = −35.5o
(b) τ max = (
σ x = 22.5 MPa
y’
10 MPa
x
o
35.5
x’
10 MPa
13.23 MPa
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