ﺗﻤﺎرﯾﻦ ﻣﺤﻠﻮﻟﺔ:اﻟﺪوال اﻷﺻﻠﯿﺔ أﻛﺎدﻳﻤﯿﺔ اﻟﺠﮫﺔ اﻟﺸﺮﻗﯿﺔ اﻟﻤﺴﺘﻮى :اﻟﺜﺎﻧﯿﺔ ﺑﺎك ﻋﻠﻮم ﻓﯿﺰﯾﺎﺋﯿﺔ وﻋﻠﻮم اﻟﺤﯿﺎة واﻷرض واﻟﻌﻠﻮم اﻟﺰراﻋﯿﺔ ﺗﻤﺮﯾﻦ :1ﻧﻌﺘﺒﺮ اﻟﺪاﻟﺔ fاﻟﻤﻌﺮﻓﺔ ﻋﻠﻰ ¡ ﻛﺎﻟﺘﺎﻟﻲ: اﻟﺪاﻟﺔ f ﺣﺪد داﻟﺔ Fﻗﺎﺑﻠﺔ ﻟﻼﺷﺘﻘﺎق ﻋﻠﻰ ¡ ﺑﺤﯿﺚ ) ( "x Î ¡ ) ; F ¢ ( x ) = f ( x ﺗﻮﺟﺪ .2 ھﻞ .3 ﻛﻢ ﺗﻮﺟﺪ ﻣﻦ داﻟﺔ Fﺑﺤﯿﺚ ) ( "x Î ¡ ) ; F ¢ ( x ) = f ( x؟ ) ( "x Î ¡ ) ; G ¢ ( x ) = f ( x داﻟﺔ أﺧﺮى ﺑﺤﯿﺚ G اﻷﺟﻮﺑﺔ (1:اﻟﺪاﻟﺔ اﻟﻤﻌﺮﻓﺔ ﻛﺎﻟﺘﺎﻟﻲ : F ( x ) = 1 x3 + x 2 + 3 xﻗﺎﺑﻠﺔ ﻟﻼﺷﺘﻘﺎق 3 ﻋﻠﻰ ¡ وﺗﺤﻘﻖ ) ( "x Î ¡ ) ; F ¢ ( x ) = f ( x ﻧﻘﻮل أن F :داﻟﺔ أﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ fﻋﻠﻰ ¡ (2اﻟﺪاﻟﺔ اﻟﻤﻌﺮﻓﺔ ﻛﺎﻟﺘﺎﻟﻲ : G ( x ) = 1 x 3 + x 2 + 3 x + 2ﻗﺎﺑﻠﺔ ﻟﻼﺷﺘﻘﺎق ﻋﻠﻰ ¡ ¡ x a k; k Î xax 2 x ¡ + c; c Î 2 اﻟﺪاﻟﺔ f *x a x n ; n Î ¥ 1 n+1 ¡x + c; c Î n +1 1 ¡ x a - + c; c Î x 1 -n+1 xa ¡x +c; cÎ -n +1 xa ( 1 }; n Î ¥* - {1 xn xa 1 xa x )}x a xr ; r Î( ¤* -{-1 اذن أﯾﻀﺎ G :داﻟﺔ أﺻﻠﯿﺔ أﺧﺮى ﻟﻠﺪاﻟﺔ fﻋﻠﻰ ¡ (3ھﻨﺎك ﻋﺪد ﻻﻣﻨﺘﮫ ﻣﻦ اﻟﺪول اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ f وﻧﻘﻮل ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ fﻋﻠﻰ ¡ ھﻲ xa ﺣﯿﺚ kﻋﺪد ﺣﻘﯿﻘﻲ. ﺗﻤﺮﯾﻦ :2ﻧﻌﺘﺒﺮ اﻟﺪاﻟﺔ fاﻟﻤﻌﺮﻓﺔ ﻋﻠﻰ [ ]0; +¥ﻛﺎﻟﺘﺎﻟﻲ: f ( x ) = 2x2 + x + 1 + .1 ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ fﻋﻠﻰ []0; +¥ .2 ﺣﺪد اﻟﺪاﻟﺔ اﻷﺻﻠﯿﺔ Fﻟﻠﺪاﻟﺔ fﺑﺤﯿﺚ F (1) = 3 1 اﻷﺟﻮﺑﺔ f ( x ) = 2 x + x + 1 + 1: 2 x2 1 1 1 اذن F ( x ) = 2 ´ x2+1 + x1+1 +1x - 2 + k : 3 2 x 2 1 3 2 F ( x) = x + x + x - 1 + kﺣﯿﺚ ¡ k Î 3 2 x 2 3 1 2 1 F (1) = 3 (2ﯾﻌﻨﻲ ´1 + ´1 +1 - + k = 3 3 2 1 7 2 1 ﯾﻌﻨﻲ + +1 -1 + k = 3ﯾﻌﻨﻲ + k = 3 6 3 2 ﯾﻌﻨﻲ 11 7 =k ﯾﻌﻨﻲ k = 3 - 6 6 وﻣﻨﮫ اﻟﺪاﻟﺔ اﻷﺻﻠﯿﺔ Fﻟﻠﺪاﻟﺔ fﺑﺤﯿﺚ F (1) = 3 xa اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ f ﻋﻠﻰ ﻣﺠﺎل I ) 3 1 x2 اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ f ﻋﻠﻰ ﻣﺠﺎل I ¡ x a kx + c; c Î 1 xa 2 x وﺗﺤﻘﻖ أﯾﻀﺎ ) ( "x Î ¡ ) ; G ¢ ( x ) = f ( x 1 3 اﻟﺪوال اﻟﻤﻌﺮﻓﺔ ﻋﻠﻰ ¡ ﺑﻤﺎ ﯾﻠﻲ x + x 2 + 3 x + k : 3 ﻧﺠﯿﺐ ﻋﺜﻤﺎﻧﻲ ﺟﺪاول ﺗﻤﻜﻨﻨﺎ ﻣﻦ اﻟﺒﺤﺚ ﻋﻦ اﻟﺪوال اﻷﺻﻠﯿﺔ f ( x ) = x2 + 2x + 3 .1 اﻷﺳﺘﺎذ: ) x a cos ( x ) x a sin ( x 1 )cos2 ( x = )x a1+ tan2 ( x ¡ x a 2 x + c; c Î 1 r +1 xa ¡ x + c; c Î r +1 ¡ x a sin ( x ) + c; c Î ¡x a -cos ( x) + c;c Î ¡ x a tan ( x ) + c; c Î اﻟﺪاﻟﺔ fﻣﻌﺮﻓﺔ ﻋﻠﻰ ﻣﺠﺎل I داﻟﺔ أﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ f ﻋﻠﻰ اﻟﻤﺠﺎل I u+v uv¢ + vu ¢ uv *u¢u n ; n Î ¥ 1 n+1 u n +1 u ¢ + v¢ u¢ u2 }¢ r ;r Î ¤* -{-1 uu ) u¢ u u ¢v - uv¢ v2 ( 1 u - 1 r +1 u r +1 2 u u v 2 1 1 11 ھﻲ اﻟﺪاﻟﺔ اﻟﻤﻌﺮﻓﺔ ﻛﺎﻟﺘﺎﻟﻲ F ( x) = x3 + x2 + x - + : 3 2 x 6 1 اﻷﺳﺘﺎذ :ﻧﺠﯿﺐ ﻋﺜﻤﺎﻧﻲ http:// xyzmath.e-monsite.com k Î ¡ ﺣﯿﺚF ( x ) = - 1 1 + k اذن 3 3 x +2 : ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪوال اﻟﺘﺎﻟﯿﺔ:3ﺗﻤﺮﯾﻦ 4 1 f ( x) = + cos x + sin x -1 (2 f ( x ) = 5x + 3x +1 (1 : ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪوال اﻟﺘﺎﻟﯿﺔ:5ﺗﻤﺮﯾﻦ x (2 f x = 2 2 x + 1 (1 ( ) f ( x) = x x2 + 1 f ( x ) = ( 2 x - 1) (4 f ( x) = sin x + x cos x (3 3 1 2 f ( x ) = 2 2 x + 1 = ( 2 x + 1)¢ ( 2 x + 1) (1: k Î ¡ ﺣﯿﺚ x au¢( ax +b) ; aΡ*;bΡ 1 x a u ( ax + b ) a 1 F ( x) = 1 +1 2 ( 2x +1) 1 +1 2 أﺟﻮﺑﺔ f ( x) = اذن +k - 1) (5 2 f ( x) = 5x + 3x +1 (1: أﺟﻮﺑﺔ 4 k Î ¡ ﺣﯿﺚF ( x) = 2 ( 2x +1) 2 + k وﻣﻨﮫ 3 k Î ¡ ﺣﯿﺚF ( x ) = 5 ´ 1 x5 + 3´ 1 x2 + 1x + k اذن 3 k Î ¡ ﺣﯿﺚF ( x) = 2 ( 2x +1) = 2 ( 2x + 1) + k وﻣﻨﮫ 3 2 5 3 3 (x x 2 f ( x) = 3 ( x + 1)¢ 2 2 1 x + cos x + sin x -1(2 (2 k Î ¡ ﺣﯿﺚF ( x ) = 2 x + sin x - cos x - x + k اذن k Î ¡ ﺣﯿﺚF ( x) = x2 + 1 + k اذن f ( x) = sin x + x cos x = x¢sin x + x (sin x)¢ (3 x f ( x) = x2 + 1 = 2 x2 + 1 : ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪوال اﻟﺘﺎﻟﯿﺔ:6ﺗﻤﺮﯾﻦ 2 (2 f ( x ) = x x 2 + 1 (1 f ( x ) = sin ( 4 x - 1) (3 f ( x ) = x k Î ¡ ﺣﯿﺚF ( x) = x ´ sin x + k اذن 1 3 3 f ( x ) = ( 2 x - 1) = ( 2 x - 1)¢ ( 2 x - 1) (4 f ( x ) = ( sin x) cos x (5 f ( x ) = cos ( 2 x + 8 ) (4 k Î ¡ ﺣﯿﺚF ( x) = 1 ´ 1 ( 2x -1)3+1 + k اذن 8 + x3 2 2 1 1 f ( x ) = x x + 1 = ( x2 + 1)¢ ( x2 + 1) 2 (1: 2 2 F ( x) = 1 1 ( x2 +1) 21 +1 2 1 +1 2 +k = 2 3 +1 k Î ¡ ﺣﯿﺚF ( x) = 1 ( 2x -1)4 + k وﻣﻨﮫ أﺟﻮﺑﺔ 8 اذن 1 2 x + 1) + k ( 3 3 2 ( 3 ) f ( x) = - ( x - 1)¢ 2 (x 2 x2 8 + x3 = 3 3 ¢ 2 (8 + x ) 3 2 8 + x3 3 - 1) (5 f ( x) = x2 ( x + 2) : أﺟﻮﺑﺔ 2 3 f ( x) = 8x3 + 4x2 + x + 6 (1 1 2+1 ( sin x) + k وﻣﻨﮫ 2 +1 k Î ¡ F ( x) = 1 ( sin x)3 + k ﯾﻌﻨﻲ 3 1 1 1 4 1 F ( x) = 8´ x4 + 4´ x3 + x2 + 6x + k = 2x4 + x3 + x2 + 6x + k اذن 4 3 2 3 2 [0; +¥[ اﻟﻤﻌﺮﻓﺔ ﻋﻠﻰf ﻧﻌﺘﺒﺮ اﻟﺪاﻟﺔ:7ﺗﻤﺮﯾﻦ k Î ¡ ﺣﯿﺚf ( x) = 2sinx +cos x -3x +k F ( x) = x + 2x : ﻛﺎﻟﺘﺎﻟﻲ 2 ( x + 1) .1 : ﺑﺤﯿﺚb وa ﺣﺪد اﻟﻌﺪدﯾﻦ اﻟﺤﻘﯿﻘﯿﯿﻦ f ( x) = 2 "x Î [ 0; +¥ [ f ( x ) = a + F (1) = (x 2 : ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪوال اﻟﺘﺎﻟﯿﺔ:4ﺗﻤﺮﯾﻦ 3 2 f ( x) = 2cos x -sin x -3 (2 f ( x) = 8x + 4x + x + 6 (1 2 2 (3 f ( x ) = ( 4 x + 5 ) (4 f ( x) = 2xsinx+ x cosx k Î ¡ F ( x) = - 1 cos ( 4x - 1) + k اذنf ( x ) = sin ( 4 x - 1) (3 4 k Î ¡ F ( x) = 1 sin ( 2x + 8) + k اذنf ( x ) = cos ( 2 x + 8) (4 2 2 2 f ( x ) = ( sin x ) cos x (5 f ( x ) = ( sin x )¢ ( sin x) ﯾﻌﻨﻲ (5 x 2 x -1 (2 k Î ¡ ﺣﯿﺚF ( x) = 2 8 + x3 + k اذن ﯾﻌﻨﻲf ( x ) = - k Î ¡ ﺣﯿﺚF ( x) = 1 + k اذن 2 k Î ¡ ﺣﯿﺚF ( x) = 1 x2 +1 + k وﻣﻨﮫ f ( x ) == - 1) 2 5 ﺑﺤﯿﺚ 2 f ﻟﻠﺪاﻟﺔF ﺣﺪد اﻟﺪاﻟﺔ اﻷﺻﻠﯿﺔ 2 f ( x) = a + b ( x + 1) a ( x + 1) + b 2 = f ( x) = ( x + 1) x + 2x 2 ( x + 1) 2 = .2 ax + 2ax + a + b 2 ( x + 1) : ﺑﺎﻟﻤﻘﺎرﻧﺔ ﻣﻊ اﻟﻜﺘﺎﺑﺔ 2 http:// xyzmath.e-monsite.com 2 k Î ¡ ﺣﯿﺚF ( x) = x2 ´ sin x + k اذن f ( x ) = ( 4 x + 5 ) (4 1 2 ( 4 x + 5)¢ ( 4 x + 5 ) 4 1 1 2+1 F ( x) = ´ ( 4x + 5) + k اذن 4 2 +1 f ( x ) = ( 4 x + 5) = 2 (1:أﺟﻮﺑﺔ 2 f ( x) = 2x sin x + x2 cos x = ( x2 )¢ sin x + x2 ( sin x)¢ (3 2 b ( x + 1) k Î ¡ ﺣﯿﺚ f ( x) = 2cos x -sin x -3(2 k Î ¡ ﺣﯿﺚ k Î ¡ ﺣﯿﺚF ( x) = 1 ( 4x + 5)3 + k وﻣﻨﮫ 12 æ ¢ 3 1 ç ( x + 2) f (x) = - ç 3 ç ( x3 + 2 )2 è ö ÷ ÷ ÷ ø ﯾﻌﻨﻲf ( x ) = ﻧﺠﯿﺐ ﻋﺜﻤﺎﻧﻲ:اﻷﺳﺘﺎذ x2 ( x3 + 2 ) (5 2 2 : c ì= ï= وﻣﻨﮫïc í ïa= ïî= b ìc = 5 ﯾﻌﻨﻲïï8c = 40 í ïa = 20 ïîb + 16c = 80 5 5 20 0 : f ( x= ) f ( x ) = 10 ( x 2 + 4 )¢ (x "x Î [0; +¥[ 15 k= 2 ﯾﻌﻨﻲ 2 + 4) 2 +5 ﯾﻌﻨﻲf ( x=) (x أن ﻧﺠﺪ 20 x +5 2 + 4) 20 x (x 2 + 4) 2 2 f ( x) = 1- ( x + 1) 2 : ﻧﺠﺪ أن ﯾﻌﻨﻲf ( x ) = 1 - (2 ( x + 1)2 + k : وﻣﻨﮫ í ï b = -1 î ( x + 1)¢ ( x + 1) "x Î [0; +¥[ +5 (2 ìa = 1 : وﻣﻨﮫï a = 1 ﯾﻌﻨﻲï 2a = 2 f ( x) = 1- 2 í ïa + b = 0 î k Î ¡ F ( x) = x + 1 x +1 1 f ﻧﻌﺘﺒﺮ اﻟﺪاﻟﺔ:8ﺗﻤﺮﯾﻦ f ( x ) = x x - 1 : [ ﻛﺎﻟﺘﺎﻟﻲ1; +¥ [ اﻟﻤﻌﺮﻓﺔ ﻋﻠﻰ k Î ¡ F ( x) = - 10 + 5x + k : وﻣﻨﮫ 2 "x Î [1; +¥ [ x +4 10 - + k = 5 ﯾﻌﻨﻲF ( 0 ) = 5 (3 4 "x Î [0; +¥[ F ( x) = - 210 + 5x + 15 : وﻣﻨﮫ x +4 2 5 k = 5+ 2 ìa = 1 1 3 ( x - 1) + x - 1 : ﺑﯿﻦ أن F ( 2 ) = 1 ﺑﺤﯿﺚf ﻟﻠﺪاﻟﺔF ﺣﺪد اﻟﺪاﻟﺔ اﻷﺻﻠﯿﺔ ﯾﻌﻨﻲ f ( x) = .1 .2 :أﺟﻮﺑﺔ ( x -1) + x -1 = ( x -1) ´ x -1+ x -1 = x -1 ´ x -1+ x -1(1 3 2 x - 1 ³ 0 ﯾﻌﻨﻲx ³ 1 : اذنx Î [1; +¥[ : ﻧﻌﻠﻢ أن x -1 = x -1 : وﻣﻨﮫ اذن : = + x-1 x x-1-1 x-1+ x-1 x x-1 ( x-1= ) + x-1 ( x-1) ´ x-1= 3 ﯾﻌﻨﻲf ( x ) = ( ) 1 1 3 1 3 + x - 1 (2 3 1 ( x -1)¢ ( x -1)2 + ( x -1)¢ ( x -1) 2 = = f ( x) ( x -1= ) 2 + ( x -1) 2 ( x -1) 2 + ( x -1) 2 3 ( x - 1) اذن 3 1 5 3 1 1 2 2 +1 +1 = F ( x) = x -1) 2 + x -1) 2 + k x -1) 2 + ( x -1) 2 + k ( ( ( 3 1 5 3 +1 +1 2 2 k Î ¡ ﺣﯿﺚF ( x) = 2 5 ( ) 5 x -1 + 2 3 ( ) x - 1 + k وﻣﻨﮫ 3 : اﻟﻤﻌﺮﻓﺔ ﻋﻠﻰ ¡ ﻛﺎﻟﺘﺎﻟﻲf ﻧﻌﺘﺒﺮ اﻟﺪاﻟﺔ:9ﺗﻤﺮﯾﻦ 5 x 4 + 40 x 2 + 20 x + 80 f ( x) = (x + 4) 2 c وb وa ﺣﺪد اﻷﻋﺪاد اﻟﺤﻘﯿﻘﯿﺔ "x Î [ 0; +¥[ f ( x) = ax + b (x 2 + 4) 2 +c 2 .1 : ﺑﺤﯿﺚ f ﺣﺪد ﻣﺠﻤﻮﻋﺔ اﻟﺪوال اﻷﺻﻠﯿﺔ ﻟﻠﺪاﻟﺔ F ( 0 ) = c ﺑﺤﯿﺚf ﻟﻠﺪاﻟﺔF ﺣﺪد اﻟﺪاﻟﺔ اﻷﺻﻠﯿﺔ f ( x) = ax + b (x 2 + 4) 2 +c = « c’est en forgeant que l’on devient forgeron » dit un proverbe. c’est en s’entraînant régulièrement aux calculs et exercices que l’on ax + b + c ( x + 4) 2 (x 2 + 4) : أﺟﻮﺑﺔ 2 2 f ( x) = f ( x) = = ax + b + cx + 8cx2 + 16c 4 (x 2 + 4) 2 cx4 + 8cx2 + ax + ( b +16c ) 5 x 4 + 40 x 2 + 20 x + 80 ( x2 + 4) .2 .3 (x 2 + 4) 2 : ﺑﺎﻟﻤﻘﺎرﻧﺔ ﻣﻊ اﻟﻜﺘﺎﺑﺔ 2 devient un mathématicien http:// xyzmath.e-monsite.com ﻧﺠﯿﺐ ﻋﺜﻤﺎﻧﻲ:اﻷﺳﺘﺎذ 3