72 www.bestcours.net .& 8-KNO3(s)$ A '4 6@ I'7 "! c = 2, 0 ×10 mol ⋅ L−1 b;7 K $ A 'Y f I 0 ", Y& f I 0 l=1,0 cm]qS=1,0 cm²]'0 > ": −3 λ NO3− = 7,1 × 10 −3 S ⋅ m 2 ⋅ mol −1 . λ K + = 7,4 × 10 −3 S ⋅ m 2 ⋅ mol −1 )8V@ eau KNO3(s) → K (+aq ) +NO3(− aq ) ).& 8-KNO3(s)$ A '4 6@ "! σ = (λK + + λNO − ) × c )$ A 'Y f ", 3 c = 2, 0mol ⋅ m −3 )=J_0 mol ⋅ m −3 5 mol ⋅ L−1 # ;7 ' /0=3I −3 −2 −1 σ == (7, 4 + 7,1).10 × 2 = 2,9.10 S .m )CBA −4 S −2 10 −4 G = σ × = 2,9 × 10 × −2 = 2,9 ×10 S. )Y& f ": l 10 K = ]'' f & 1U L V$ 0,05 mol.L-1b;7 6J 79Y f 1U 0,01 m G = 10 mS Y& 9 f I 0 "! 896J f& r& 45 7] & f& l''$ ", 0,005 S.m2.mol G = K ⋅ σ ) ' UX@V f & f& ?@"! σ = G 0,010 = = 1,0 S .m −1 )4 K 0,010 I'(.& 8-6J 794 6@ [ Na + ] = [OH − ] = C 6J 79Y 8-", NaOH ( S ) → Na(+aq ) + OH (−aq ) )=( σ = Σλi [ X i ] = λ Na × [ Na + ] + λOH × [OH − ] )9Y& f @-8' Ù σ = λ Na × C + λOH × C Ù σ = C × (λ Na + λOH ) www.bestcours.net + − + − + λOH = − σ C − − λ Na + Ù (λ Na + + λOH − ) = σ C Ù 1,0 − 0,005 = 0,015 S ⋅ m 2 ⋅ mol −1 )CBA 50 −3 mol ⋅ m 5 mol ⋅ L−1 # ;7 ' /0= ΔχϮΤϠϣ λOH = − 73 [ =7/0 6 λ & f& c8& ;7 ' σ f& #R 8' UX@ 74"! 5×10-3 mol·L-1.b;7 (Ag + + NO3- ) GN A 'Y f 25°C60", 13.3 mS.m-189H'f r7 45 GN A 'Y&8& ;7 ' I 0 ": 2 -1 + 2 -1 λ(N O3− ) = 7,14 mS.m .mol λ(Ag ) = 6,19 mS.m .mol )8V@ σ = λi ⋅ ci )λ & f& c8& ;7 ' σ f& #R 8' UX@ "! i ) 89 f& /0 mol ⋅ m −3 ) 89 ;7 ' /0 S.m2.mol-1 )89 λ & f& /0 g www.bestcours.net S·m-1 σ = (λAg + λNO ) ⋅ c ) GN A 'Y f ", + − 3 c = 5 mol·m-3 =J- mol ⋅ m −3 5 mol ⋅ L−1 # ;7 ' /0Y σ = (6,19 + 7,14) ×10−3 ⋅ 5 = 6, 66 ×10−2 S·m-1 )45 c = σ λAg + λCl + = − 0, 0133 = 1mol ⋅ m −3 = 10−3 mol ⋅ L−1 ) GN A '8& ;7 ' ": −3 (6,19 + 7,14) × 10 Mg2+(aq) + 2 ;h& A '8S Y '@ C0b;7 NO3 –(aq) H<l' Y&@'$;7 ' K9 1U L V$ ]$U?Y& K]G f & ]'' G = 0,025 S]'&Ur(-K = 0,1 m Y& K9 f I 0 "! iY&8& ;7 ' & YXL# l''$ ", mol.m-3 60λNO3- = 0,00714 S.m2.mol-1 &": Mg2+X & f& &U l' &H<& = @& @60"F λMg2+λNO3- G 0,025 σ = = = 0,25 S ⋅ m −1 )45 G = Kσ )Y& f "! K 0,1 C0 = 10 3C0 = 0,010 mol.L-1 σ = 0, 25 S ⋅ m −1 f& [- & ;7 ' &U & YXL# ", www.bestcours.net mol.m-3 C09;h& A ';7 &": 2+ – [NO3 ] = 2 × C0[Mg ] = C0) σ = Σλi [ X i ] = λNO × 2C0 + λMg × C0 )9 f& @-8' − 2+ 3 λMg = 2+ 0, 25 σ − 2 × 0, 00714 = 0, 011 S ⋅ m 2 ⋅ mol −1 )CBA λMg 2+ = − 2λNO − )45 3 10 C0 x = C y = σ g y = a × xH'6@ ?@& =f3# &?[' #/ σ = f (C ) Y=E&& & "F a = (2λNO + λMg − 3 2+ H<& = @& a ) )9H<& = @& 45 σ = C × (2λNO + λMg ) Ù σ = λNO × 2C + λMg × C ) 74 − 2+ − 3 2+ 3 )# (& 8' R> 178- G www.bestcours.net 0,02 mol/Lb;7 *( P&0Y # 30 mLj 0,01 mol/Lb;7 6J 79Y # 10 mLj 878S&( Y' '@ )8V@ ion Na+ ClH3O+ HO -3 -3 -3 -3 -1 λ Sm²mol 5,01 10 7,63 10 34,98 10 19,86 10 6J 79*( +&0#=N' S&( 6@& I'7 "! JU [' & =N'& 60=N' [Y<3", S] Y& 8-/< '& A ;7 I 0 ": S] 8-R>σ f& 60"F H 3 + O + H O - H 3O + + HO- → 2H 2 O )=N' 6@ "! ", =N' 6@ 2 H 2 O → n1 =0,03 × 0,02 = 6 10-4 mol n 2 =0,01× 0,01 = 10-4 mol 6 10-4 -x 10-4 -x 6 10-4 -xmax 10-4 -xmax oIK n/ - S / - / - =N' YXL S] )9JU [' OH 7] 9& =N'& - n1 = 6 10 mol n 2 = 10 mol ) & xmax=10-4 mol ) S] 8-A ;7 ": − n [Na ]f = + n f ( Na + ) Vt -4 -4 n i ( Na + ) 0,01× 10 = = 2,5.10-3mol L-1 = 2,5mol.m -3 )6J ;7 j Vt ( 30+10 ) oT N' HkV h'H6 &745=N' 8- M 6J n f ( Cl- ) n i ( Cl- ) 0,02 × 30 9( n [Cl ]f = = = = 1,5.10-2 mol L-1 = 15mol.m -3 )( ;7 j Vt Vt 40 - oT N' Lu o =N' n OH − f = n f ( OH Vt − ) = 10 −4 − xm = 0mol / L ) 7] ;7 j Vt n f ( H 3O + ) 6.10-4 − xm 5.10-4 [H 3O ]f = = = = 1,25.10-2 mol L-1 =12,5mol.m -3 ) 7 ;7 j -3 Vt Vt 40.10 + σ = λCl . Cl − + λNa . Na + + λOH . OH − + λH O . H 3O + )"F σ =10-3 ( 34,98 × 12,5 + 7,63 ×15+5,01× 2,5) = 0,564 S.m -1 )CBA − + − + 3 www.bestcours.net 75 =J-25°C/ <6 V[& .& 8- Fe3 ( PO4 ) 2 ,8H 2 O H&& II AN$-# m '7IK 439 mS.m-1H'f Y H&& II AN$-4 6@ I'7 "! /< '& AX & AXf& *K7Y&C;7 ' Y& f @R ", Y&C8& ;7 ' 60": Y& K9# 1,00 L.YJ cX i K& '7l''$ "F λ PO = 27,84 mS ⋅ m 2 ⋅ mol −1 λ Fe = 10,70 mS ⋅ m 2 ⋅ mol −1 )8V@ www.bestcours.net 2+ 3− 4 Fe3 ( PO4 ) 2 ,8H 2 O( S ) → 3 Fe(2aq+ ) + 2 PO43− ( aq ) + 8 H 2 O( L ) )H&& II AN$-4 6@ "! σ = Σλi [ X i ] ) ?@", 2+ 3− PO4 Fe )&9Y&#< '& # σ = λ Fe × [ Fe 2+ ] + λ PO × [ PO43− ] )9 f& @45 2+ σ = C (3λ Fe 2+ 3− 4 [ PO43− ] = 2 × C [ Fe 2+ ] = 3 × C )- ' 7' AX @& ' + 2λ PO ) Ù σ = λ Fe × 3C + λ PO × 2C )^J f& @45 3− 4 2+ 3− 4 σ = C (3λ Fe + 2λ PO ) )": 2+ C = 3− 4 σ (3λ Fe 2 + + 2λ PO 3− ) )4 4 C = 0,439 = 5,00 mol ⋅ m −3 )CBA −3 (3 × 10,70 ⋅ 10 + 2 × 27,84 ⋅ 10 ) −3 5,00 × 10-3 mol.L-1)-mol.L-1/0 5Y )Y& # 1,00 L.YJ cX i K& '7"F M = 3 × M Fe + 2 × M P + 8 × M O + 8 × M H O )i K& & '( 3I M = 3 × 55,8 + 2 × 31,0 + 8 × 16,0 + 8 × 18,0 = 501 g ⋅ mol −1 )CBA n = C × V)=( I'(/6& &7C = 5,00 × 10-3 mol.L-1)9i K&8& ;7 ' & m = C × V × MÙm = n × M)89i K& '7m = 5,00 × 10-3 × 1,00 × 501 = 2,51 g)CBA 2 )AV@ )25°C / <6 & Af& + -3 2 λ(Na (aq)) = 5,01.10 S.m .mol-1;λ(HCOO-(aq)) = 5,46.10-3 S.m2.mol-1 M(C) = 12 g.mol-1 ; M(H) = 1 g.mol-1 ; M(O) = 16 g.mol-1 ; M(Na) = 23 g.mol-1 ) & ='( 8-HCOONa(s)6J A E # m = 68,0 mg '7 4~8S Y&V = 100,0 mL&0 Gj V[& .& www.bestcours.net .& 8-6J A E 4 6@ I'7 "! c;7 ' I 0 M(HCOONa(s)) V ,m Y&c8& ;7 ' @R ", Y& 8-/< '& AX8@N 8& ;7 ' I 0 ": ]'&UI 0 ?c;7 ' Y&σ1 f& @R "F #S ' #6 '( # (' f L &h?k Y& 5 V[& .& # V’&0QGj U = 1,00 =J-S = 3,21 cm2&h& .; 0 L = 1,00 cm - &]=JN#c ' @-/V #'NJ #&h& Y& 8-/ I = 2,47 mA k > '?G f & I 0 "x Y&σ2 f& l''$ "y QN>& Y&c’8& ;7 ' I 0 " * <X@ V[& .&V’? l''$ " 76 www.bestcours.net HCOONa(s) → HCOO-(aq) + Na+(aq)).& 8-6J A E 4 6@ "! n m )Y&c8& ;7 ' @", c = 0,010 mol.L-1)CBAc = = V (M × V) )Y& 8-/< '& AX8@N 8& ;7 ' ": + n ( Na (aq) ) = n ( HCOO (aq) ) = n ( HCOONa (s ) ) =c × V )=N' 6@ YXL# [Na+(aq)] = [HCOO-(aq)] = 0,010 mol.L-1 = 10 )CBA[Na+(aq)] = [HCOO-(aq)] = c)45 mol.m-3 σ1 = λ(Na+(aq)) × [Na+(aq)] + λ(HCOO-(aq)) × [HCOO-(aq)])Y&σ1 f& @"F σ1 = (λ(Na+(aq)) + λ(HCOO-(aq))) × c)-[Na+(aq)] = [HCOO-(aq)] = c) & σ1 = (5,46.10-3 + 5,01.10-3) × 10 = 1,05.10-1 S.m-1)CBA I 2,47.10-3 G = = = 2,47.10-3 S)G f & i 0"x U 1,00 L 1,00.10-2 = 31,2 m-1) k > ' k= = S 3,21.10-4 σ2 = k × G = 2,47.10-3 × 31,2 = 7,69.10-2 S.m-1)Y&σ2 f& "y )QN>& Y&c’8& ;7 ' " + σ2 = (λ(Na (aq)) + λ(HCOO (aq))) × c’)45c’;7 'c;7 ' R[- h fFY a UX[ c’ = σ2/(λ(Na+(aq)) + λ(HCOO-(aq))))-8' c’ = 7,69.10-2/(5,46.10-3 + 5,01.10-3) = 7,35 mol.m-3)C"A n = c’ × (V+ V’))-8'i K& ? /6 &7 h'QN>' &YXL) V[& .&V’? " -3 -3 -1 -2 V’ = 1,0.10 /7,35.10 - 1,0.10 = 3,6.10 L = 36 mL)CBAV’ = n/c’ – V)45 # &h& .; f (_C1b;7 6J (S1Y # 100 mL8- f L &h G1 = 1,22 mS89#6 '( #Y& .; f (_C2b;7 6J (S2Y # 100 mL8- f & L`N &h? G2 = 1,44 mS89#6 '( #Y& # &h& C2;7 ' # hf 3 7 C1;7 ' 7 4 #i 0"! Y& 8- [ f & L &h? S1Y # 100 mL5 V[& .& # 100 mLQG", Y& K]G3 f & &Ul''$ C1 H=J& Y&C;7 ' 9 H=J& Cb;7 -(H=J& Y& #S2Y # 100 mLS1Y # 100 mLT;&": Y&G4 f & &UI 0 ?C2C1#;7 ' V$' &U=E& Y&C2;7 ' # hf S1Y&C1;7 ' )-Y& ;7 g 6 q I$'G f & &"! S2 www.bestcours.net G3. = 77 G1 C )89Y& K9 f -8' C = 1 b;7 -QJ 5QNLY& &", 2 2 G3 = 0,61 Ms)CBA n n +n C ×V + C ×V C = = 1 2 = 1 1 2 2 )H=J& Y& ;7 ": Vt Vt Vt V C1 + C2 )- V1 = V2 = t ) & C2C1#;7 ' V$' &U=E&C;7 ' -8' C = 2 2 G + G2 G4 = 1 = 1,33 mS )-Y& ;7 g 6 q I$'G f & & 2 + -3 2 -l λ(K ) = 7,35. 10 S. m .mol ; λ(Cl-) = 7,63. 10-3 S. m2.mol-l) & f& )AV@ 8S Y # .;< f =< # =&@' & 8 ' I7 ' =E&=(c?U"! -3 c = 5,00.10 b;7 (K+ + Cl-)$ ((S1)8S Y # .;<1 f L V$ ", mol.L-1 I1 = 3,52 89Y& 8-& 8S ]( ' /-U1 = 0,800 V#'NJ 8V # ' ( mA Y& # &h& .;G1 f & I 0 !", U2 = 0,500 V 08-]$U#(&& I2' /89 ,", (S1)Y&σ1 f& I 0 k$AV@& & f&*'@'$:", 'E bK] V & = @ 89 k > ' [ O$ # l''$ F", -3 -1 c = 5,00.10 mol.L b;7 ' Rb+ + Cl- ((S2)Y g [ > `N=&@' ": G2 = 4,53 .10-3 SH'f f& l''$ Cl-Rb+# # =( & f& (S2)Y&σ2 f& @R λ(Rb+) & =J& (S3) Y&σ3 f& @< (S2)Y& # 100 mL(S1)Y& # 100 mLT;&"F ]'&UI 0 ?σ2σ1 H )=&@' & 8 ' I7 ' "! # '&VN R 8 ' / 8- ' R _0 '/ & 6;#08- f & 1U L8V i' )Y& # &h& .;G1 f& !", G1 =I1/U1 = 3,52.10-3/0,800 = 4,40.10-3 S )- h'Y&G f & &)I2' /,", I2 = G1 × U2 = 2,2.10-3 A)4 G1 = I2/U2 )(S1)Y&σ1 f& :", + + + σ1 = λ(K ) × [K ] + λ(Cl ) × [Cl ] = c × (λ(K ) + λ(Cl-)) = 0,0749 S.m-1 k = σ1/G1 = 17,0 m-14 σ1 = k × G1) ?@)k > 'F", σ2 = λ(Rb+) × [Rb+] + λ(Cl-) × [Cl-] = c × (λ(Rb+) + λ(Cl-)(S2)Y&σ2 f& @": )) + ) λ(Rb ) & f& k × G2 σ2 = k × G2 = 0,0770 S.m-1λ(Rb+) = - λ(Cl-) =7,79.10-3 S.m2.mol-1 c )(S3) Y&σ3 f& @"F 78 + + + + σ3 = λ(Rb ) × [Rb ]’ + λ(Cl ) × [Cl ]’ + λ(K ) × [K ]’ ) )(S3)Y& 8-A ;7 I [Rb ]'= + www.bestcours.net n ( Rb + ) V1 + V2 [K ]'= + [Cl ]'= - = n (K+ ) V1 + V2 n ( Cl- ) V1 + V2 = c × V1 c + = ) Rb A ;7 j V1 + V2 2 = c × V2 c + = )K A ;7 j V1 + V2 2 c × V1 + c × V2 = c )Cl A ;7 j V1 + V2 + λ(Rb ) λ(K+) σ1 σ2 σ3 = c × ( + λ(Cl ) + ) = + = 0,0760 S.m-1)45 2 2 2 2 www.bestcours.net