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Test for Cations and Anions in
Aqueous Solutions
November 30, 2020 by Veerendra
Test for Cations and Anions in Aqueous
Solutions
Test for anions in aqueous solutions
1. When a salt is dissolved in water, the free anion will be present in the aqueous solution.
Tests can then be carried out to identify the anion.
2. The following shows the various con몭rmatory tests for carbonate ion, chloride ion,
sulphate ion and nitrate ion in aqueous solutions.
Test for carbonate ion, CO32Method:
Add dilute hydrochloric acid.
Bubble gas through limewater.
Observation:
Limewater turns milky.
What happened?
Acids react with carbonate ion to produce carbon dioxide gas.
CO32-(aq) + 2H+(aq) → CO2(g) + H2O(l)
Carbon dioxide turns limewater milky due to the formation of calcium carbonate (white
precipitate).
CO2(g) + Ca(OH)2(aq) → CaCO3(s) + H2O(l)
Test for chloride ion, Cl–
Method:
Add dilute nitric acid.
Then add silver nitrate solution.
Observation:
A white precipitate is obtained.
What happened?
Silver ion, Ag+, from silver nitrate combines with chloride ion, Cl–, to form the silver
chloride.
Ag+(aq) + Cl–(aq) → AgCl(s)
Silver chloride is an insoluble salt and forms as a white precipitate.
The nitric acid added is to prevent precipitation of silver sulphate and silver carbonate.
Test for sulphate ion, SO42Method:
Add dilute hydrochloric acid.
Then, add barium chloride solution.
Observation:
A white precipitate is obtained.
What happened?
Barium ion, Ba2+, from barium chloride combines with the sulphate ion, SO42-, to form
barium sulphate.
Ba2+(aq) + SO42-(aq) → BaSO4(s)
Barium sulphate is an insoluble salt and forms as a white precipitate.
The hydrochloric acid added is to prevent precipitation of barium carbonate.
Test for nitrate ion, NO3–
Method:
Add dilute sulphuric acid.
Then, add iron(II) sulphate solution.
Shake to mix well.
Carefully add concentrated sulphuric acid down the side of the test tube.
Observation:
Brown ring is obtained.
What happened?
Concentrated sulphuric acid reacts with the nitrate ion to form nitrogen monoxide
molecule, NO.
Nitrogen monoxide combines with iron(II) sulphate to form a brown complex which
appears as a brown ring.
This test is also known as the ‘brown ring test’.
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Test for anions examples
1. Some tests were carried out on salt P. The results obtained were shown below.
Test
Observation
No residue was left in the test tube.
1. Salt P was heated.
A gas was evolved which turned red litmus
paper blue.
2. Salt P was dissolved in water.
Dilute nitric acid was added, followed by
A white precipitate was formed.
silver nitrate solution.
Identify salt P.
Solution:
The gas liberated is ammonia because it is an alkaline gas. Hence, ammonium ion is present.
Anion is a chloride ion because silver chloride is precipitated. Salt P is ammonium chloride.
2. Figure shows the reaction scheme of a compound Q.
Identify compound Q.
Solution:
The gas is carbon dioxide. Q contains a carbonate ion. Zinc oxide is yellow when hot and
white when cold. Hence, Q is zinc carbonate.
Test for cations in aqueous solutions
1. Test for the presence of some common cations such as:
ammonium ion, NH4+
aluminium ion, Al3+
calcium ion, Ca2+
lead(II) ion, Pb2+
magnesium ion, Mg2+
copper(II) ion, Cu2+
iron(II) ion, Fe2+
iron(III) ion, Fe3+
zinc ion, Zn2+
2. Aqueous solutions containing the above cations can be prepared by
(a) dissolving a soluble salt in water.
(b) dissolving an insoluble base in dilute acids.
3. Except for ammonium ion, the rest of the cations in the list are metal ions. They
combine with hydroxide ions to form insoluble metal hydroxide.
4. Two common laboratory reagents that can supply the hydroxide ions needed to test for
cations are:
(a) sodium hydroxide solution
(b) ammonia solution
Test for cations in aqueous solutions
experiment
Aim: To test for metal cations in aqueous solution.
Materials: 1 mol dm-3 solutions of aluminium nitrate, ammonium chloride, magnesium
nitrate, calcium nitrate, lead(II) nitrate, zinc nitrate, iron(II) sulphate, iron(III) chloride,
copper(II) sulphate; 2.0 mol dm-3 sodium hydroxide solution, 2.0 mol dm-3 ammonia solution
and red litmus paper.
Apparatus: Test tubes, beakers and dropper.
Procedure:
A. Using sodium hydroxide solution to test for metal cations
1. About 2 cm3 of aluminium nitrate solution is poured into a test tube.
2. A dropper is used to add sodium hydroxide solution drop by drop to the solution in the
test tube. The mixture is shaken after each addition of alkali.
3. Any changes that occur are noted.
4. If a precipitate is produced, the addition of sodium hydroxide solution is continued until
in excess. The mixture is shaken well after each addition of alkali.
5. Observation on whether the precipitate dissolves in excess alkali is noted.
6. Steps 1 to 5 are repeated using each of the cation solutions listed in Table to replace
aluminium nitrate solution.
B. Using ammonia solution to test for metal cations
1. Steps 1 to 6 in section A are repeated using ammonia solution to replace sodium
hydroxide solution.
2. The results are recorded in a table.
Observations:
Observation
Cation solution
Cation
Sodium hydroxide solution
Ammonia solution
White precipitate.
Aluminium
nitrate
Al3+
Dissolves in excess alkali to
White precipitate.
produce a colourless
Insoluble in excess alkali.
solution.
Calcium nitrate
Copper(II)
sulphate
Ca2+
Cu2+
White precipitate.
Insoluble in excess alkali.
Blue precipitate.
Insoluble in excess alkali.
No precipitate.
Blue precipitate.
Dissolves in excess alkali to
produce a dark blue solution.
Iron(II) sulphate
Fe2+
Iron(III) chloride
Fe3+
Green precipitate. Insoluble
Green precipitate.
in excess alkali.
Insoluble in excess alkali.
Brown precipitate.
Brown precipitate.
Insoluble in excess alkali.
Insoluble in excess alkali.
White precipitate.
Lead(II) nitrate
Pb2+
Dissolves in excess alkali to
White precipitate.
produce a colourless
Insoluble in excess alkali.
solution.
Magnesium
nitrate
Mg2+
White precipitate. Insoluble in
White precipitate.
excess alkali.
Insoluble in excess alkali.
White precipitate.
Zinc nitrate
Zn2+
Dissolves in excess alkali to
produce a colourless
White precipitate.
Dissolves in excess alkali to
produce a colourless
solution.
Ammonium
chloride
NH4+
No precipitate.
solution.
No precipitate.
Discussion:
1. Sodium hydroxide solution is a strong alkali, providing a high concentration of
hydroxide ions. Hence, it is able to precipitate all the metal cations used.
2. The weaker ammonia solution is unable to ionise fully to provide a high concentration
of hydroxide ions needed to precipitate calcium ions.
3. Transition metal cations form coloured precipitate, whereas non-transition metal
cations form white precipitate.
4. Aluminium hydroxide, lead(ll) hydroxide and zinc hydroxide dissolve in excess sodium
hydroxide solution due to their amphoteric property, that is, they exhibit both acidic and
basic properties.
5. Copper(II) hydroxide and zinc hydroxide dissolve in excess ammonia solution because
they are able to form complex ions with ammonia molecules.
Conclusion:
Most metal ions can be precipitated in the form of metal hydroxides.
Con몭rmatory tests for Fe2+, Fe3+, Pb2+ and
NH4+ ions
Ammonium ion, NH4+
Method I: Heating an ammonium salt with a strong alkali
(a) Procedure:
(i) About 2 cm3 of ammonium chloride solution is poured into a test tube.
3
(ii) About 4 cm3 of dilute sodium hydroxide solution is added to the test tube and the mixture
is shaken well.
(iii) The mixture is carefully heated and the gas liberated is tested with a piece of moist red
litmus paper.
(b) Observation:
The colourless gas evolved turns red litmus paper blue.
(c) Explanation:
Heating an ammonium salt with an alkali produces ammonia gas.
NH4+(aq) + OH–(aq) → NH3(g) + H2O(l)
The alkaline ammonia gas turns red litmus paper blue.
Method II: Reacting with Nessler’s reagent
(a) Procedure:
(i) About 2 cm3 of ammonium chloride solution is poured into a test tube.
(ii) A dropper is used to add Nessler’s reagent drop by drop to the solution.
(iii) Any change that occurs is noted.
(b) Observation:
A brown precipitate is formed.
(c) Explanation:
Ammonium ion reacts with a complex ion in Nessler’s reagent to produce a brown
precipitate.
Iron(II) ion, Fe2+
(a) Procedure:
(i) About 2 cm3 of iron(II) sulphate solution is poured into a test tube.
(ii) A dropper is used to add potassium hexacyanoferrate(III), K3Fe(CN)6 solution, drop by
drop into the test tube.
(iii) Any change that occurs is recorded.
(b) Observation:
A dark blue precipitate is obtained.
(c) Explanation:
The iron(II) ion combines with a complex ion in the reagent to produce a dark blue
precipitate.
Fe2+(aq) + Fe(CN)63-(aq) → dark blue precipitate
Iron(III) ion, Fe3+
Method I: Reacting with potassium hexacyanoferrate(II), K4Fe(CN)6 solution
(a) Procedure:
(i) About 2 cm3 of iron(III) chloride solution is poured into a test tube.
(ii) A dropper is used to add potassium hexacyanoferrate(II) solution drop by drop into the
test tube.
(iii) Any change that occurs is noted.
(b) Observation:
A dark blue precipitate is formed.
(c) Explanation:
The iron(III) ion combines with a complex ion in the reagent to produce a dark blue
precipitate.
Fe3+(aq) + Fe(CN)64+(aq) → dark blue precipitate
Method II: Reacting with potassium thiocyanate, KSCN solution
(a) Procedure:
(i) About 2 cm3 of iron(III) chloride solution is poured into a test tube.
(ii) A dropper is used to add potassium thiocyanate solution drop by drop into the test tube.
(iii) Any change that occurs is recorded.
(b) Observation:
A blood-red colouration is seen.
(c) Explanation:
The thiocyanate ion from potassium thiocyanate combines with iron(III) ion to form a bloodred colouration.
Fe3+(aq) + SCN–(aq) → FeSCN2+(aq) (blood red)
Lead(II) ion, Pb2+
Method I: Reacting with sodium chloride
(a) Procedure:
(i) About 2 cm3 of lead(II) nitrate solution is poured into a test tube.
(ii) A dropper is used to add about 1 cm3 of sodium chloride solution into the test tube.
(iii) About 3 cm3 of distilled water is added and the mixture is boiled.
(iv) The mixture is then cooled using running water from the tap.
(v) Any change that occurs is recorded.
(b) Observation:
A white precipitate which dissolves in hot water and reappears when cooled is formed.
(c) Explanation:
Chloride ion from sodium chloride combines with lead(II) ion to form a white precipitate of
lead(II) chloride.
Pb2+(aq) + 2Cl–(aq) → PbCl2(s)
The precipitate is insoluble in cold water but dissolves in hot water.
Method II: Reacting with potassium iodide
(a) Procedure:
(i) About 2 cm3 of lead(II) nitrate solution is poured into a test tube.
(ii) A dropper is used to add about 1 cm3 of potassium iodide solution into the test tube.
(iii) About 3 cm3 of distilled water is added and the mixture is boiled.
(iv) The mixture is then cooled using running water from the tap.
(v) Any change that occurs is recorded.
(b) Observation:
A yellow precipitate which dissolves in hot water is formed.
On cooling, golden yellow crystals are formed.
(c) Explanation:
Iodide ion from potassium iodide combines with lead(II) ion to form a yellow precipitate of
lead(II) iodide.
Pb2+(aq) + 2I–(aq) → PbI2(s)
The precipitate is insoluble in cold water but dissolves in hot water.
Cation
NH4+
Sodium hydroxide
solution
Ammonia gas evolved
when mixture is heated.
Mg2+
Ca2+
White precipitate.
Insoluble in excess alkali.
White precipitate.
Insoluble in excess alkali.
Ammonia solution
–
Other reagent
Nessler’s reagent: brown
precipitate
White precipitate.
Insoluble in excess
–
alkali.
No precipitate.
Concentrated H2SO4:
white precipitate
Kl(aq): yellow precipitate
Pb2+
White precipitate.
White precipitate.
NaCl(aq): white
Soluble in excess alkali to
Insoluble in excess
precipitate
form colourless solution.
alkali.
Na2S04(aq): white
precipitate
Al3+
White precipitate.
White precipitate.
Soluble in excess alkali to
Insoluble in excess
form colourless solution.
alkali.
White precipitate.
Zn2+
Soluble in excess alkali to
form colourless solution.
Fe2+
Fe3+
Green precipitate.
Insoluble in excess alkali.
Brown precipitate.
Insoluble in excess alkali.
–
White precipitate.
Soluble in excess alkali
–
to form colourless
solution.
Green precipitate.
Insoluble in excess
alkali.
Brown precipitate.
Insoluble in excess
alkali.
K3Fe(CN)6: dark blue
precipitate KMn04: purple
colour of the solution is
decolourised
K4Fe(CN)K6: dark blue
precipitate
KSCN: blood-red
colouration
Blue precipitate.
Cu2+
Blue precipitate.
Soluble in excess alkali
Insoluble in excess alkali.
to form dark blue
–
solution.
Identifying the anions and cations in
unknown salts
1. Use the knowledge you have- learnt about the reactions of anions and cations to help
you plan and carry out experiments to identify the anions and cations in an unknown
salt.
2. This knowledge can also help you write the correct observations and make inferences
or conclusions about the identities of anions and cations.
3. When carrying out tests on a salt:
(a) plan your experiment carefully
(b) be systematic and meticulous
(c) use correct techniques
(d) always follow safety procedures
4. The salt is dissolved in water or dilute acid.
5. The 몭rst step in qualitative analysis of a salt is to obtain an aqueous solution of the
given salt.
6. A soluble salt will dissolve in water to produce ions in aqueous solution.
7. Insoluble salts such as an insoluble carbonate can be dissolved in dilute nitric acid to
produce ions in aqueous solutions.
Identifying the anions and cations
examples
1. Q1 is a simple salt. Carry out the following tests to identify the salt.
Experiment
Observation
Deduction
Colourless gas which
rekindles glowing
wooden splint is
Heat Q1 strongly in a
liberated.
test tube.
Brown gas which
Identify any gas
turns moist blue
liberated.
litmus paper red is
Keep residue for part
liberated.
Hot brown residue
turns yellow when
cold.
Oxygen gas is
liberated.
Nitrogen dioxide gas is
liberated. NO3– ion is
present.
Residue may be PbO.
Allow the test tube to
cool.
Dissolve the residue in
dilute nitric acid. For
separate portions of
the resulting solution,
(i) add ammonia
solution until in excess
(ii) add sodium
hydroxide solution
until in excess
Dissolve 1 spatulaful
of Q1 in distilled water.
Add potassium iodide
solution, boil and cool
under the running tap
water.
Transition metal ions
Residue dissolves to
are absent.
produce a colourless
Insoluble metal
solution.
hydroxide is formed.
White precipitate.
Mg2+, Pb2+ or Al3+ ion
Insoluble in excess
may be present.
ammonia.
Insoluble metal
White precipitate.
hydroxide is formed.
Soluble in excess
Amphoteric metal
alkali to form a
hydroxide.
colourless solution.
Pb2+ or Al3+ ion may
be present.
A colourless solution
Transition metal ions
is obtained.
are absent.
A yellow precipitate is
Yellow precipitate is
formed.
lead(II) iodide which
Precipitate dissolves
dissolves in hot water
in hot water to form a
and reappears on
colourless solution.
cooling.
On cooling, yellow
Pb2+ ion is con몭rmed
crystals are formed.
to be present.
Salt Q1 contains lead(II) ion, Pb2+, and nitrate ion, NO3+. Q1 is lead(II) nitrate.
2. Q2 is a salt containing one cation and one anion. Identify the ions from the following tests.
Experiment
Observation
Deduction
Fe3+ ion may be
present.
2+
Orange solution is
obtained.
Dissolve 1 spatulaful of Q2 in
distilled water. Use separate
portions of the solution for
the following tests. Add
(a) potassium iodide solution
(b) sodium hydroxide
solution until in excess
(c) ammonia solution until in
excess
(d) dilute nitric acid, followed
by silver nitrate solution
(e) dilute hydrochloric acid,
followed by barium chloride
solution
(f) potassium thiocyanate
solution
No precipitate.
Brown precipitate.
Insoluble in excess
alkali.
Brown precipitate.
Insoluble in excess
alkali.
Effervescence
occurs.
Colourless gas turns
limewater milky. No
white precipitate.
Effervescence
occurs.
Colourless gas turns
limewater milky. No
white precipitate.
Blood red
colouration.
Pb2+ ion is
absent.
Iron(III) hydroxide
is precipitated.
Fe3+ ion is
present.
Iron(III) hydroxide
is precipitated.
Fe3+ ion is
present.
Carbon dioxide
gas is liberated.
CO32- ion is
present.
Cl– ion is absent.
Carbon dioxide
gas liberated.
C032- ion is
present.
S042- ion is
absent.
Fe3+ ion is
con몭rmed to be
present
Colourless gas is
Place 3 spatulaful of Q2 in a
liberated. The gas
test tube. Heat strongly.
turns limewater
Test the gas liberated.
milky. Brown residue
obtained.
Carbon dioxide
gas is liberated.
C032- ion is
present.
Residue is iron(lll)
oxide.
Q2 is iron(III) carbonate as it contains iron(III) ion, Fe3+, and carbonate ion, CO32- .
Filed Under: Chemistry
Tagged With: Identifying the anions and cations, Identifying the anions and cations in unknown salts,
Test for Anions, Test for anions in aqueous solutions, Test for Cations, Test for Cations and Anions, Test
for Cations and Anions in Aqueous Solutions, Test for cations in aqueous solutions, Test for cations in
aqueous solutions experiment
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